x^2+5.98x-13.03=0

Solution for x^2+5.98x-13.03=0 equation:

x^2+5.98x-13.03=0

a = 1; b = 5.98; c = -13.03;
Δ = b2-4ac
Δ = 5.982-4·1·(-13.03)
Δ = 87.8804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.98)-\sqrt{87.8804}}{2*1}=\frac{-5.98-\sqrt{87.8804}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.98)+\sqrt{87.8804}}{2*1}=\frac{-5.98+\sqrt{87.8804}}{2}
$